492,407 views
25 votes
25 votes
What is one solution to the trigonometric equation 3cosx − sin2x + 3 = 0 in the interval [0, 2π]?

What is one solution to the trigonometric equation 3cosx − sin2x + 3 = 0 in the interval-example-1
User Tomcheney
by
3.0k points

2 Answers

7 votes
7 votes

Answer:

the answer is d. pi

Explanation:

User Zeromus
by
3.3k points
10 votes
10 votes

x = π

STEP - BY - STEP EXPLANATION

What to find?

The solution to the given trigonometric equation.

Given:

3cosx - sin²x + 3 = 0

We first need to note that:

sin²x = 1- cos²x

To find the solution to the given trigonometric equation, we will follow the steps below:

Step 1

Replace sin²x in the given equation by 1 - cos²x.

That is;

3cosx - (1 - cos²x ) + 3 = 0

Step 2

Simplify and re-arrange.

3cosx - 1 + cos²x + 3 = 0

3cosx + cos²x + 2 = 0

cos²x + 3cosx + 2 = 0

Step 3

Let y = cosx

That is;

y² + 3y + 2 = 0

Step 4

Solve the resulting quadratic equation using factorization method.

y² + 2y + y + 2 = 0

y(y+2) + 1( y + 2) = 0

(y + 1)(y + 2) = 0

Either y = -1 or y = - 2

Step 5

Substitute back y=cosx

cosx = -1 or cosx = -2

The only defined solution that we will pick is cosx = -1

Step 6

Find the arc cos of both-side of the equation.


x=\cos ^(-1)(-1)

x = 180 degree = π

Therefore, the correct option is π.

User Andunslg
by
2.6k points