Question

PLZ HELP ME! what is the solution set to the inequality 6z + 5 >35?

a. (z:z < 5)
b. (z:z < 24)
c. (z:z > 24)
d. (z:z >24)

Answer 1

6z+5>35

Subtract 5 from both sides

6z+5-5>35-5

6z > 30

Divide both sides by 6

6z/6 > 30/6

z > 5

I hope that's help !