Question

Does anyone seriously know how to do these

Answer 1

Thats simple!
h(x)=
`(x^(2)+3x )/(4x+27)`
find h(-8)
All we need to do is PLUG IN THE -8
h(-8)=
`((-8)^(2)+3(-8) )/(4(-8)+27)`
=
`(64-24)/(-32+27)` (negative²=positive, negative×positive=negative)
=
`(40)/(-5)`
h(-8)=-8