Question

a bag contains eight red marbles and 8 blue marbles. what are the chances of drawing a red marble without replacing it, and then drawing a blue marble.A. 1/16 = 0.063B. 4/15=0.267C. 1/4 =0.25D. 35/132=0.265

Answer 1

Let:

A = Draw a red marble

B = Draw a blue marble

so:

`\begin{gathered} P(A)=(8)/(16)=(1)/(2) \\ P(B)=(8)/(15) \\ so\colon \\ P(A)\cdot P(B)=(1)/(2)\cdot(8)/(15)=(8)/(30)=(4)/(15)=0.267 \end{gathered}`