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Use special right triangles to solve for the values of x. Round answer to the nearest tenth if necessary.
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45 votes
Use special right triangles to solve for the values of x. Round answer to the nearest tenth if necessary.

Use special right triangles to solve for the values of x. Round answer to the nearest-example-1
User Neilcrookes
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1 Answer

27 votes
27 votes

By Trigonometric Ratio,


\begin{gathered} \sin 60=\frac{5\sqrt[]{3}}{x} \\ \text{Cross multiply to get,} \\ x=\frac{5\sqrt[]{3}}{\sin 60}=\frac{5\sqrt[]{3}}{\frac{\sqrt[]{3}}{2}} \\ \\ x=\frac{2*5\sqrt[]{3}}{\sqrt[]{3}}=2*5=10 \end{gathered}

So, the value of x is 10.

User Kristoffer
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