30.0k views
3 votes
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)

2 Answers

6 votes

Answer:


(g-f)(3)=23

Explanation:

Given :
f(x) = 4 -x^2 and
g(x) = 6x

To find : The value of
(g -f)(3)

Solution :

First we find the value of (g-f)


(g-f)(x)= g(x)-f(x)


(g-f)(x)=6x-(4-x^2)


(g-f)(x)=6x-4+x^2

Now, put the value of x=3


(g-f)(3)=6(3)-4+(3)^2


(g-f)(3)=18-4+9


(g-f)(3)=23

Therefore,
(g-f)(3)=23

User ProxyTech
by
8.7k points
5 votes
For this case we have the following functions:

f (x) = 4 - x ^ 2 g (x) = 6x
The first thing we must do is subtract both functions.
We have then:

(g - f) (x) = g (x) - f (x)
Substituting values we have:

(g - f) (x) = (6x) - (4 - x ^ 2)
Rewriting we have:

(g - f) (x) = x ^ 2 + 6x - 4
Then, we evaluate the function for x = 3.
We have then:

(g - f) (3) = 3 ^ 2 + 6 (3) - 4
Rewriting:

(g - f) (3) = 9 + 18 - 4 (g - f) (3) = 23
Answer:
An expression that is equivalent to (g - f) (3) is:

(g - f) (3) = 23
User Jeeppp
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories