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A basketball is picked up off the ground and carried to the top of a platform that is 160 feet up. It is then dropped to the ground. The ball rebounds one-half the height each time it hits the ground. What is the total vertical distance the ball will travel from the moment it is picked up to the moment it reaches its maximum height after the fourth bounce

User Stuxen
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1 Answer

5 votes

Answer:

Step-by-step explanation:

The total distance travelled by ball before first bounce

= 160 + 160 = 320 ft

Distance travelled between first bounce and second bounce

= 80 + 80 = 160 ft

Distance travelled between second bounce and third bounce

= 40 + 40 = 80 ft

Distance travelled between third bounce and fourth bounce

= 20 + 20 = 40 ft .

Distance travelled in fourth bounce = 10 ft

Total distance travelled = 320 + 160 + 80 + 40 + 10

= 610 ft .

User Born Ready
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