Question

Please help me                          llxl+2l=2

Answer 1

There is only one solution to the problem and that is x=0.

Answer 2

`||x|+2|=2`

if x≥0 then |x|=x
if x<0 then |x|=-x

1) for x≥0


`|x+2|=2 \\ x+2=2 \ \lor \ x+2=-2 \\ x=0 \in D \ \lor \ x=-4 \\otin D`


2) for x<0


`|-x+2|=2 \\ -x+2=2 \ \lor \ -x+2=-2 \\ -x=0 \ \lor \ -x=-4 \\ x=0 \\otin D \ \lor \ x=4 \\otin D`

The answer is:

`x=0`