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At how many points does the graph of the function y=16x^2-8x+1 intersect the x axis

User Fishhead
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2 Answers

3 votes

Answer:

im pretty sure that its 1

User Gui Moura
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4 votes
ok so this is the equaiton of a porabola
also, the number of roots/xintercept<degree of the equation
this equation is 2n degree (highest power=2)

so we can factor it and find te roots
x intercept is when y=0 so
0=16x^2-8x+1
factor
0=(4x-1)(4x-1)
since the 2 roots are the same, there is 1 solution, ie. there is one intersection of the x axis the bottom of the parabola is tangent to the x axis)


1 point
User Rmv
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7.5k points