Answer: Option (a) is the correct answer.
Step-by-step explanation:
Valence electrons are the electrons present in the outermost shell of an atom.
Atomic number of beryllium is 4 and its electronic distribution is 2, 2. This means there are only two shells of electrons.
Whereas atomic number of sodium is 11 and its electronic distribution is 2, 8, 1. This means there are three shells of electrons.
Also there is one more valence electron in sodium as compared to beryllium.
Thus, we can conclude that out of the given options the element X is sodium (Na).