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45 votes
Reflex the arrow over the -y axis. I have pic below explanation for the problem?

Reflex the arrow over the -y axis. I have pic below explanation for the problem?-example-1
User Tamim Shahriar
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2.5k points

1 Answer

15 votes
15 votes

In order to reflect a shape over the y-axis, we just have to change the sign of the x-coordinates of its points. In this case, we have an arrow with points A(2,1), B(2,3), C(1, 3), D(3,5), E(5, 3), F(4,3), and G(4, 1). By applying the reflection over the y-axis we get:

A(2,1) -> A'(-2,1)

B(2,3) -> B'(-2,3)

C(1,3) -> C'(-1,3)

D(3,5) ->D'(-3,5)

E(5,3) -> E'(-5, 3)

F(4,3) -> F'(-4,3)

G(4,1) -> G'(-4, 1)

Then, by reflecting the arrow we should get:

Reflex the arrow over the -y axis. I have pic below explanation for the problem?-example-1
User Morishiri
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3.0k points