Question

sodium reacts with chlorine to form sodium chloride, explain how in terms of electrons, atoms and ions

Answer 1

A sodium atom has one electron in the outer shell. A chlorine atom seven electrons in the outer shell. A sodium atom loses an electron to a chlorine atom. the sodium ions and chloride ions form an ionic lattice

Step-by-step explanation:

Answer 2

Sodium is in group 1 so it has 1 valence electron (one electron in its outer shell). Sodium will be looking to lose its one valence electron in order to become more stable. Chlorine is in group 17 so it has 7 valence electrons, and therefor only needs to gain one valence electron to attain noble gas electron configuration (become stable with 8 valence electrons, just like the noble gases in group 18 have 8). Because the chlorine atom is trying to gain one electron, and the sodium atom is trying to lose one, sodium will give up its one valence electron to chlorine and the two atoms will form an ionic bond. Because chlorine is looking to gain just one electron and sodium is looking to lose the same number, the ratio of chlorine atoms to sodium atoms will be 1:1, one chlorine atom per one sodium atom.