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How can complex fractions be used to solve problems involving ratios?

User Jrotello
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Answer:

Explanation:

User Ryde
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When you have ratios, and some unknowns, you can create complex fractions from them. Bring them to the same denominator, and solve for x.

Example - we have this proportion:
2-x
5-45
And we can change it into fraction:

(2)/(5)=(x)/(45)


(2*9)/(5*9)=(x)/(45)


(18)/(45)=(x)/(45)
18=x

In case of more complex fractions it may come in handy.
User Suruj
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