Question

If you have 25.0 ml of a 6.50m naoh solution and you add 10.0 ml of water to it, what is the new concentration?

Answer 1

36.5ml is the new concentration so, its a chemical change if there's something new

Answer 2

Step-by-step explanation:

The given data is as follows.

`V_(1)` = 25.0 ml,
`V_(2)` = (10.0 ml + 25.0 ml) = 35.0 ml

`M_(1)` = 6.50 M,
`M_(2)`

Relation between volume and molarity of the two liquids is as follows.

`M_(1) * V_(1)` =
`M_(2) * V_(2)`

`6.50 M * 25.0 ml` =
`M_(2) * 35.0 M`

`M_(2)` = 4.64 M

Thus, we can conclude that new concentration is 4.64 M.