How to find an equation of the line that passes through the point(-3,-2) and is parallel to 2x=3-5y?

asked Sep 25, 2018 3.6k views

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3-5y= 2x

-5y= 2x-3

y= (-2/5)x + 3/5

y + 2 = (-2/5)(x + 3)

y + 2 = (-2/5)x - (6/5)

y + 10/5 = (-2/5)x - 6/5

y = (-2/5)x - 16/5 is the answer

Mehmood answered Oct 2, 2018

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