Question

Which of these equations is a perpendicular line to y = 6/5x + 1y = 5x - 3y = 5/6x + 3y = 6/5x + 1y = -5/6x + 3y = 6/5x + 3

Answer 1

`y=-(5)/(6)x+3`

Step-by-step explanation

The given line equation is

`y=(6)/(5)x+1`

For two equations that are perpendicular with slopes m₁ and m₂,

m₁ m₂ = -1

From all the options given, only equation y = -5/6(x) + 3 will be perpendicular to the given line equation.

m₁ = 6/5 and m₂ = -5/6

Hence,

`\begin{gathered} (6)/(5)*-(5)/(6)=-1 \\ \text{This satisfies m}_1m_2=-1 \end{gathered}`