Question

1.

m =
y2 - y1
x2 - x1


What is the slope of line segment EF?

A)
1/3


B)
3/2


C)
2/3


D)
3/2




2. Find the slope of the line that passes through points A and D.

A)
7/2


B)
2/7


C)
0


D)
2/7




3.
m =
y2 - y1
x2 - x1


What is the slope of line segment JK?

A)
5/9


B)
9/5


C)
5/9


D)
9/5




(4)9.Determine the equation of the line given by the graph.

A)
y = 2x + 4


B)
y = 4x + 2


C)
y =
1/2
x − 2


D)
y = −2x + 4




(5)10.Triangle ABC and triangle CFG are similar right triangles. Which proportion can be used to show that the slope of AC is equal to the slope of CG?

A)
0 − 2
3 − 0
=
2 − 6
9 − 3


B)
0 − 2
3 − 0
=
6 − 2
9 − 3


C)
2 − 0
3 − 0
=
6 − 2
9 − 3


D)
3 − 0
2 − 0
=
9 − 3
6 − 2


all the pictures are in order

Answer 1

1. B) 3/2
2. choices B and D have the same choice . But I know the answer is 2/7.
3. choices A and C have the same choice. The answer is -5/9 which, none of the options have a negative but I know that is the answer.
4. i dont know
5. I dont know

Answer 2

1). Slope =
`(3)/(2)`

2). Slope =
`(2)/(7)`

3). Slope =
`-(5)/(9)`

4). Option A. 2x + 4

5). Option C.
`(2-0)/(3-0)=(6-2)/(9-3)`

Explanation:

1). Slope of a line segment EF with E(-2, -4) and F(2, 2)

Slope m =
`(-4-2)/(-2-2)`

m =
`(-6)/(-4)`

m =
`(3)/(2)`

2). Slope of a line segment AD with A(-3, -2) and D(4, 0)

Slope m =
`(-2-0)/(-3-4)`

m =
`(2)/(7)`

3). Slope of a line JK with J(-4, 2) and K(5, -3)

m =
`(-3-2)/(5+4)`

m =
`-(5)/(9)`

4). We have to determine the equation of the line given by graph.

In other words we have to determine the eequation of a line passing through (0, 4) and (-2, 0)

Equation will be in the form of y = mx + c

Where c = y-intercept = 4 units

Slope m =
`(4-0)/(0+2)=(2)`

Therefore, equation of the line will be y = 2x + 4

Option A. 2x + 4 is the answer.

5). If triangles ABC and CFG are similar then AC and CG will have same slope.

Slope of AC with A(0,0) and C(3, 2) = Slope of CG with C(3, 2) and G(9, 6)

`(2-0)/(3-0)=(6-2)/(9-3)`

Therefore, Option C. is the correct option.