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The science club purchased tickets for a magic show. They paid $108 for 6 tickets in section A and 10 tickets in section B.

The following week, they paid $104 for 4 tickets in section A and 12 tickets in section B.

What is the price for tickets in section A?

User Jerclarke
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1 Answer

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let x is the price for one ticket in section A and y for section B.
In first week they paid $108 for 6 tickets in section A and 10 tickets in section B.
So,
6x + 10y = 108
And in the following week, they paid $104 for 4 tickets in section A and 12 tickets in section B.
So,
4x + 12y = 104
12y = 104 -4x
y= (104 -4x) /12
now, put this value for y in first equation
6x +10(104 - 4x / 12) = 108
multiplying all terms with 12
72x +10(104 -4x) = 1296
72x + 1040 -40x = 1296
32x = 256
x = 8
So, price for one ticket in section A is $8.

User Jfrank
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