Answer:
New temperature T2 = 16.59°C Approx
Step-by-step explanation:
Given:
Old volume V1 = 2.36 L
Old temperature T1 = 27°C
New volume V2 = 1.45 L
Find:
New temperature T2
Computation:
Using Charles's Law;
V1T2 = V2T1
(2.36)(T2) = (1.45)(27)
New temperature T2 = 16.59°C Approx