Answer:
8secs
Explanation:
To calculate how long the ball stays in air, we need to find the time it takes to reach the max height first
The ball reaches its max height when dh/dt = 0.
-32t+128=0
32t = 128
t = 128/32
t = 4secs
The time the ball spent in air will be;
t = 2(4)
t = 8secs
Hence the ball spent 8secs in air