Question

When a phasor-domain circuit has dependent sources, you should not use a sequence of source transforms to find the thévenin and norton equivalents for that circuit, and you cannot use the equivalent impedance technique to find the equivalent impedance. instead, you must find the open-circuit phasor voltage (which is the thévenin voltage) and the short-circuit phasor current (which is the norton current). then you can use ohm's law with the phasor voltage and current to find the thévenin (or norton) impedance. remember that you can also use the test source method to find the thévenin impedance. consider the circuit shown here. in this circuit, the phasor voltage source vs=10∠0∘ v. we wish to find the norton equivalent of this circuit to the left of terminals a and

b?

Answer 1

To analyze AC circuits, it is important to consider the phase relationship of voltages across different components and use Ohm's Law to determine the total current and impedance. The Norton equivalent of a circuit can be derived from the open-circuit voltage and short-circuit current, along with applying Ohm's Law to find the impedance.

Step-by-step explanation:

Understanding AC Circuit Analysis

In the analysis of AC circuits with phasors, it is crucial to account for the phase relationships of voltages across resistors (R), inductors (L), and capacitors (C). In such circuits, voltages across these components are not simply additive due to their phase differences. Ohm's Law is applied to find the total current (I) using the source voltage (Vo) and the total impedance (Z). When components like resistors, inductors, and capacitors are connected together, the impedance is not purely resistive, and we must contend with reactance (X).

The total impedance of a circuit can be represented by Z where Z is a complex number that considers both resistance and reactance. Resistor voltage (VR) is in phase with the current, while inductor voltage (VL) leads current by 90°, and capacitor voltage (Vc) lags current by 90°. As a result, VL and Vc can partially or entirely cancel each other out if their magnitudes are equal since they are 180° out of phase. Their peak values do not simultaneously align, meaning the source voltage Vo does not equal the sum of the individual peak voltages across R, L, and C. To find the total impedance Z in terms of R, X₁, and XC, we need to account for these phase differences.

For calculating the Norton equivalent of a circuit with dependent sources, the approach usually involves finding the open-circuit voltage (which is the Thévenin voltage) and the short-circuit current (which corresponds to the Norton current). These values, along with Ohm's Law, yield the Thevenin or Norton impedance. Alternatively, the test source method can be employed to ascertain the Thévenin impedance directly.

Answer 2

yes but the answer is A