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THE THREE SIDES OF A TRIANGULAR LOT

ARE MEASURED TO BE APPROXIMATELY 100.52
FT, 15.321 FT AND 143.250 FT LONG. FIND THE
APPROXIMATE PERIMETER OF THE LOT​

User Solvek
by
3.4k points

1 Answer

14 votes

Answer:

259.09 feet

Explanation:

Given that,

The three sides of a triangular lot are measured to be 100.52 ft, 15.321 ft and 143.250 ft.

We need to find the perimeter of the lot.

We know that,

Perimeter = sum of all sides

P = 100.52 + 15.321 + 143.250

P = 259.09 feet

So, the required perimeter of the lot is 259.09 feet.

User Menelik
by
3.6k points