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Which geometric series diverges?

A. 3/5+3/10+3/20+3/40+


B. -10+4-9/5+16/25-

C.

Which geometric series diverges? A. 3/5+3/10+3/20+3/40+ B. -10+4-9/5+16/25- C.-example-1
User Shortorian
by
8.5k points

2 Answers

2 votes

Answer:

c

Explanation:

User OmerBTW
by
8.5k points
2 votes

Answer:

The correct option is C.

Explanation:

A geometric series divergent if
|r|\geq1.

In the first option the first term of the series is,


a=(2)/(5)

common ratio is


r=(3/10)/(3/5) =(1)/(2)

Since the common ratio is less than 1, therefore the geometric series is convergent and the option A is incorrect.

In the second option the first term of the series is,


a=-10

common ratio is


r=(4)/(-10) =-(2)/(5)

Since the common ratio is less than 1, therefore the geometric series is convergent and the option B is incorrect.

The nth term of a geometric series is in the form of


a_n=ar^(n-1)

So, the common ratio of option C and D are -4 and
(1)/(5) respectively.

Since the absolute common ratio in option C is more than 1. i.e.,
|-4|\geq1, therefore the geometric series is divergent and the option C is correct.

Since the common ratio in option D is less than 1, therefore the geometric series is convergent and the option D is incorrect.

User Ymotov
by
8.0k points

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