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How do you factor -3x^2+5x+12=0

User Vmanne
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2 Answers

4 votes
-3x^2 + 5x + 12 = 0

-3*12 = -36

Now 9 * -4 = -36 and 9 - 4 = +5 so we write:-

-3x^2 + 9x - 4x + 12 = 0

-3x (x - 3) -4 (x - 3) = 0

(x - 3) is common so we have the answer which is:-

(-3x - 4)(x - 3) = 0
User Monique
by
7.9k points
4 votes
-(3^2x-5x-12)=0
-(3x+4)(x-3) =0
x= 4/3 & x= -3
is the answers
User Milos Mijatovic
by
8.8k points

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