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Suppose h(x) = ax^3 + 11x^2. Determine a if h has an inflection point at x = 4. Show all your work.

User Dvorah
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2 Answers

9 votes

Answer:

This isn't the answer, but do you have the rest of the questions?

Explanation:

Thank you in advance.

User DL Studio
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3.4k points
5 votes

Answer:


a=-11/12

Explanation:

We are given the function:


h(x)=ax^3 + 11 x^ 2

And we want to determine a such that h(x) has an inflection point at x = 4.

Possible inflection points are whenever h''(x) equals 0. So, we will first differentiate h(x) twice. This yields:


h'(x)=3ax^2+22x

So:


h^(\prime\prime) (x)=6ax+22

Inflection points occur when h''(x) = 0. So:


0=6ax+22

Since we have an inflection at x = 4:


0=24a+22

And solving for a yields:


a=-22/24=-11/12

User AllocSystems
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