Question

Tell whether the equation has one, zero, or

infinitely many
solutions
4x-3 = 2x + 13
Someone help plz

Answer 1

One solution

Explanation:

4x - 3 = 2x + 13

4x − 3 − 2x = 2x + 13 − 2x (subtract 2x from both sides)

2x - 3 = 13

2x − 3 + 3 = 13 + 3 (add 3 to both sides)

2x = 16

2x/2 = 16/2 (dividing 2 from both sides)

x = 8

Answer 2

So starting with the question which is
4x-3=2x+13
All you have do is subtract 2x from 4x which is 2x
So now the equation will become
2x-3=13
Minus 3 on both sides So 2x is left over
2x=16
X=8