Question

The chemical formula for cesium chloride CsClA chemist measured the amount of the cesium chloride produced during an experiment. She finds that 9.5 g of cesium chloride is produced. Calculate the number of moles of cesium chloride produced. Be sure your answer has the correct number of significant digits

Answer 1

We know that a chemist finds that 9.5 g of cesium chloride is produced and we must find the number of moles of cesium chloride

In order to find the number of moles we must use the next formula

`\text{ number of moles}=\frac{mass}{molar\text{ mass}}`

In this case, the mass produced is given 9.5 g and the molar mass of the cesium chloride is 168.36 g/mol

Now, we must replace the values in the formula

`\text{ number of moles}=(9.5g)/(168.36(g)/(mol))`

Finally, we must simplify the equation

`\text{ number of moles}=0,0564267046804467\text{mol}`

Giving the answer using the correct number of significant digits:

`\text{ number of moles}=5.6\cdot10^(-2)\text{mol}`

ANSWER:

`5.6\cdot10^(-2)`