Question

player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to Player A, had 12 fewer runs batted in for the 2006 regular season. together, these two players brought home 248 runs during the 2006 regular season. How many runs batted did player A and player B each account for?

Answer 1

Let x be the number of batted runs for player A, then the number of batted runs for player B is x - 12

Given that both players brought home 248 runs during the 2006 regular season, this means that

x + x - 12 = 248
2x = 248 - 12 = 236
x = 236 / 2 = 118.