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Find the differential dy of y=x^3-3x Evaluate dy for x=2, dx=0.05

Find the differential dy of y=x^3-3x Evaluate dy for x=2, dx=0.05
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Find the differential dy of y=x^3-3x Evaluate dy for x=2, dx=0.05

User Jegadesh B S
by
8.3k points

1 Answer

1 vote
we find the deferential by differentiating the function dy=(3x^2-3)dx
substituting the values for x and dx
dy=(3*2^2-3)(0.05)=0.45
User Jessy
by
8.4k points
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