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At which temperature will water boil when the external pressure is 17.5 torr

User Ronak K
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Answer: The temperature required to boil will be 8.6 K

Explanation: The normal boiling point of water is taken as 100 °C

The pressure conditions at this temperature is 1 atm

Now, to calculate the temperature required to boil water present at 17.5 torr, we use Gay-Lussac's Law, which states that the pressure is directly proportional to the temperature at constant volume and number of moles.

Mathematically,


(P_1)/(T_1)=(P_2)/(T_2)

Initial conditions:


P_1=1atm=760torr


T_1=100^oC=(100+273)K=373K

Final conditions:


P_2=17.5torr


T_2=?K

Putting in above equation, we get


(760)/(373)=(17.5)/(T_2)


T_2=8.6K

User MySun
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