Question

A child rides her bike at a rate of 12.0 km/hr down the street. A squirrel suddenly runs in front of her so she applies the brakes and slows to 8.0 km/hr in 0.25 sec. What is the acceleration of the bike rider during this period?

Answer 1

it should be 16 kilometers per second

Answer 2

By v = u - at
=>8 = 12 - a x 0.25
=>a = 4/0.25 km/hr/sec
=>a = 16km/hr/sec

I hope this helped!