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-3x(x+4)+15=6-4x
This is for homework please help

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-3x(x+4)+15=6-4x

-3x^2-12x+15=6-4x

-3x^2-12x+4x+15-6=0

-3x^2-8x+9=0

this is the form

ax^2+bx+c=0
with a=-3, b=-8 and c=9

the solutions are


x=(-b\pm √(b^2-4ac))/(2a)

put a, b and c we have


x=(-4\pm √(43))/(3)
User Dveim
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