Question

Determine the correct hybridizaton (from left to right) about each interior atom in ch2=chch2cl.

Answer 1

In the molecule, CH2=CHCH2Cl, both carbon atoms are sp² hybridized.

Step-by-step explanation:

The molecule CH2=CHCH2Cl contains a carbon atom that is bonded to three other atoms: one carbon atom, one hydrogen atom, and one chlorine atom. To determine the hybridization of the carbon atom, we need to count the number of sigma bonds and lone pairs around it.

In this case, the carbon atom has one sigma bond with the hydrogen atom and one sigma bond with the chlorine atom. There are no lone pairs around the carbon atom. Based on this information, we can determine that the carbon atom is sp² hybridized.

The other carbon atom in the molecule is bonded to three hydrogen atoms. It also has no lone pairs around it. Therefore, we can conclude that this carbon atom is also sp² hybridized.

Answer 2

Answer: To determine hybridization you count the # of un-bonded PAIR of electrons. Theny you count bonded domains (a double bond still counts as one bonded domain, so does a triple bond). For the first Carbon on top, you see it bonded to 2 oxygens and 1 carbon.However, when you count up the valence electrons that would be present, there is supposed to be 2 more electrons (ONE electron pair) on carbon. To do hybridization you must also be familiar with drawing lewis structures. So when you draw the pair of un-bonded electrons on carbon, you see that there is ONE un-bonded electron pair, and THREE bonded domains. ONE plus THREE = FOUR. so that would be sp3.