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I am having trouble solving for Y. I solved for X in the second equation, but I cannot seem to figure it out by substituting for the other equation.

3x+5y=25, x-2y=-10

User Janez
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x - 2y = -10 --> x = 2y -10

3x + 5y = 25 --> 3(2y-10) + 5y = 25 --> 11y - 30 = 25 --> 11y = 55 --> y = 5

x = 2y -10 --> x = 2(5) -10 --> x =10 -10 --> x =0

Answer (0,5)
User NgocLK
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