Question

A globetrot contains 3 red balls, 2 green balls and 6 blue balls if we choose a ball then another ball without putting the first one back in the globetrot what is the probability that the first ball will be redundant the second ball will be blue?

Answer 1

Prob = (3 / 11) * (6 / 10) = 18 / 110 = 9 / 55

Step-by-step

The probability that the first is red equals 3/11 (favourable outcomes divided by possible outcomes). Under condition that this occurs the probability that the second is blue equals 6/10. The probability of the described event is then the product of these factors. This according to the rule P(A and B)=P(A)*P(B|A).

here you go sis!

Answer 2

9/55

Explanation:

I don’t like explaining :/ If this is wrong I’m terribly sorry :(