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A globetrot contains 3 red balls, 2 green balls and 6 blue balls if we choose a ball then another ball without putting the first one back in the globetrot what is the probability that the first ball will be redundant the second ball will be blue?

2 Answers

6 votes

Answer:

Prob = (3 / 11) * (6 / 10) = 18 / 110 = 9 / 55

Step-by-step

The probability that the first is red equals 3/11 (favourable outcomes divided by possible outcomes). Under condition that this occurs the probability that the second is blue equals 6/10. The probability of the described event is then the product of these factors. This according to the rule P(A and B)=P(A)*P(B|A).

here you go sis!

User AlexBalo
by
7.7k points
12 votes

Answer:

9/55

Explanation:

I don’t like explaining :/ If this is wrong I’m terribly sorry :(

User RobertoAllende
by
8.1k points

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