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A 250 gram sample of water at the boiling point had 24.0 kj of heat added. how many grams of water were vaporized? heat of vaporization for water is 40.6 kj/mole.

User Erdi Aker
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1 Answer

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Let us compute for the total moles that can be vaporized:

moles vaporized = 24 kJ / 40.6 kJ/mol

moles vaporized = 0.59 mol

The molar mass of water is 18 g/mol so the mass vaporized is:

mass vaporized = 0.59 * 18 = 10.64 grams

User Alokoko
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