71,773 views
17 votes
17 votes
Here is a graph of the equation 2y - x = 1.Are the points (0, 1/2) and (-7, -3) solutions to the equation? Explain how you know.

Here is a graph of the equation 2y - x = 1.Are the points (0, 1/2) and (-7, -3) solutions-example-1
User Wolframhempel
by
2.7k points

1 Answer

20 votes
20 votes

Given the graph of the equation:


2y-x=1

we will check if the points (0, 1/2) and (-7, -3) solutions to the equation

So, we will substitute the points into the equation

The first point (0, 1/2)

Substitute with x = 0, and y = 1/2

so,


LHS=2\cdot(1)/(2)-0=1=R\mathrm{}H\mathrm{}S

So, the point (0, 1/2) is a solution to the equation and as shown in the figure the line passes through the point which is the y-intercept

The second point (-7, -3)

Substitue with x = -7, and y = -3

so,


LHS=2\cdot-3-(-7)=-6+7=1=R.H.S

So, the point (-7, -3) is a solution to the equation.

User Max D
by
3.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.