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Here is a graph of the equation 2y - x = 1.Are the points (0, 1/2) and (-7, -3) solutions to the equation? Explain how you know.

Here is a graph of the equation 2y - x = 1.Are the points (0, 1/2) and (-7, -3) solutions-example-1
User Wolframhempel
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1 Answer

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Given the graph of the equation:


2y-x=1

we will check if the points (0, 1/2) and (-7, -3) solutions to the equation

So, we will substitute the points into the equation

The first point (0, 1/2)

Substitute with x = 0, and y = 1/2

so,


LHS=2\cdot(1)/(2)-0=1=R\mathrm{}H\mathrm{}S

So, the point (0, 1/2) is a solution to the equation and as shown in the figure the line passes through the point which is the y-intercept

The second point (-7, -3)

Substitue with x = -7, and y = -3

so,


LHS=2\cdot-3-(-7)=-6+7=1=R.H.S

So, the point (-7, -3) is a solution to the equation.

User Max D
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