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Answers and work for them please

Answers and work for them please-example-1
User Richardtz
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7.5k points

1 Answer

7 votes

Answer:

no solution

no solution

Explanation:

To solve radical equations, you need to isolate the square root and square both sides. Then at the end, you must check solutions for extraneous solutions.

10.


√(5x - 10) + 6 = 4


√(5x - 10) = -2

A square root is always a non-negative number. Since the square root on the left equals -2, there is no real solution.

11.


√(2x^2 + 8x - 4) + 6 = 5


√(2x^2 + 8x - 4) = -1

A square root is always a non-negative number. Since the square root on the left equals -2, there is no real solution.

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