Answer:
The value of p = 120 when q = 5
Explanation:
We know that if y varies inversely with x, we get the equation
y ∝ 1/x
y = k/x
k = yx
where 'k' is called the constant of proportionality.
In our case,
If p is inversely proportional to the square of q, then
p ∝ 1/q²
p = k/q²
k = pq²
As p is 30 when q is 10, so
substituting p = 30 and q = 10
k = (30) (10)²
k = (30)(100)
k = 3000
Now,
Determining the value of p when q = 5
Using the equation
p = k/q²
now substituting k = 3000 and q = 5
p = 3000 / (5)²
p = 3000/25
p = 120
Therefore, the value of p = 120 when q = 5