Question

if an average rectangular block of limestone used to build the great pyramid of khufu at giza is approximately 2.5 feet by 3 feet by 4 feet, then how much would one block weigh if limestone weighs approximately 170 pounds per cubic foot?

Answer 1

A single limestone block measuring 2.5 feet by 3 feet by 4 feet would weigh approximately 5100 pounds when using the given density of limestone at 170 pounds per cubic foot.

Step-by-step explanation:

To calculate the weight of a single limestone block used in the construction of the Great Pyramid of Khufu, first determine the volume of the block by multiplying its dimensions in feet: 2.5 feet × 3 feet × 4 feet. This results in a total volume of 30 cubic feet. Next, to find the weight, multiply the volume by the weight of limestone per cubic foot, which is approximately 170 pounds:

30 cubic feet × 170 pounds/cubic foot = 5100 pounds.

Therefore, the weight of one such limestone block would be approximately 5100 pounds.

Answer 2

Given a following rectangular block with the following dimensions:

L = Length = 4 ft.

W = Width = 3 ft.

H = Height = 2.5 ft.

To be able to determine the weight of one block, we must first determine its volume.

We get,

`\text{ Volume = L x W x H}`
`\text{ = 4 x 3 x }2.5`
`\text{ Volume = 30 ft}^3`

Let's now determine the weight of the block,

`\text{Weight of the Block = 30 (ft}^3)\text{ x }\frac{\text{ 170 lbs.}}{(ft^3)}`
`\text{ = 30 x 170 lbs.}`
`\text{ Weight of the Block = 5},100\text{ lbs.}`

Therefore, the weight of one block is 5,100 lbs.