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25 votes
What is the value of the 4th term of the expansion (a + b)^5?A. 10a^3b^2B. A^5C. 10a^2b^3D. 5a^4b

User BrettFromLA
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1 Answer

27 votes
27 votes

Using the binomial, we have:


(a+b)^n=\sum ^n_(k\mathop=0)(n!)/(k!(n-k)!)a^(n-k)b^k

Here n = 5, then


(a+b)^5=\sum ^5_{k\mathop{=}0}(5!)/(k!(5-k)!)a^(5-k)b^k

The 4th term will be when k = 3, then


(5!)/(3!(5-3)!)a^(5-3)b^3=(5!)/(3!\cdot2!)a^2b^3=10a^2b^3

The 4th term will be


10a^2b^3

The correct answer is the letter C.

User AlexAlvarez
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