Question

Write a balanced equation for the reaction of solid iodine with fluorine gas.

Answer 1

The balanced equation for the reaction of solid iodine with fluorine gas is I2(s) + 3 F2(g) → 2 IF3(g), indicating one molecule of iodine reacts with three molecules of fluorine to form two molecules of iodine trifluoride.

Step-by-step explanation:

The student asked for a balanced chemical equation for the reaction between solid iodine (I2) and fluorine gas (F2). The balanced equation for this reaction is:

I2(s) + 3 F2(g) → 2 IF3(g)

This equation indicates that one molecule of solid iodine reacts with three molecules of fluorine gas to produce two molecules of iodine trifluoride gas. In balancing the equation, it is important to ensure that the same number of each type of atom appears on both sides of the equation.

Answer 2

Iodine, I2, reacts with fluorine, F2, at room temperature to form the pentafluoride iodine(V) fluoride. At 250°C the same reaction forms the heptafluoride iodine(VII) fluoride. With careful control of the reaction conditions, (-45°C, suspension in CFCl3), it is posible to isolate the trifluoride iodine(III) fluoride. I2(s) + 5F2(g) → 2IF5(l) [colourless] I2(g) + 7F2(g) → 2IF7(g) [colourless] I2(s) + 3F2(g) → 2IF3(s) [yellow]