Answer:
![\sf N = \boxed{-2}\;M + \boxed{110}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/vzfsgoldajbtmvmco4qm7pzyug5ua3xcw8.png)
Explanation:
A trend line, also known as a line of best fit or regression line, is a straight or curved line that represents the general direction or pattern of a set of data points in a scatter plot or graph.
Trendlines are commonly used to identify patterns, make predictions, and understand the overall behavior of a dataset, and provide a visual representation of the underlying trend in the data.
The independent variable of a scatter plot is always drawn along the horizontal axis. The dependent variable of a scatter plot is always drawn along the vertical axis.
The trend line in the given scatter plot is a straight line with a negative slope. It shows the relationship between the variables M and N.
The trend line crosses the y-axis at (0, 110) and crosses the x-axis at (55, 0).
To find the slope of the trend line, substitute the two points on the line into the slope formula:
![\textsf{Slope $(m)$}=(y_2-y_1)/(x_2-x_1)=(0-110)/(55-0)=(-100)/(55)=-2](https://img.qammunity.org/2023/formulas/mathematics/middle-school/nrldesexexlcbag99d30l3xl7pmehsrxj2.png)
Substitute the found slope, m = -2, and the y-intercept, b = 110, into the slope-intercept formula, y = mx + b:
![y=-2x+110](https://img.qammunity.org/2023/formulas/mathematics/middle-school/6vomb80smos7si81k9i5keo1xzfpwgsbxm.png)
As variable M is the independent variable, substitute x = M.
As variable N is the dependent variable, substitute y = N.
Therefore, the equation of the given trend line is:
![\boxed{\sf N=-2M+110}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/55gb6ou96nw1byz90gpekmo4hju5l7cvl8.png)