Question

A compound consists of 4.50 g of nitrogen for every 7.71 g of oxygen and has the same empirical and molecular formula identify the compound

Answer 1

The compund of N2O3 has the same empirical and molecular formula when the compund consist of 4.5g of nitrogen for every 7.71 grams of oxygen.

Answer 2

`N_2O_(3)`

Step-by-step explanation:

Hi, the empirical formula is the minimal expression of the molecule composition and doesn't always represent the molecule in the reality.

On the other hand the molecular formula is a multiple of the empirical and represents how the molecule is composed in reality.

In this case they are the same.

Now, nitrogen has an atomic weight of 14 g/mol and oxygen one of 16 g/mol:

`n_(nitrogen)=(4.5g)/(14g/mol)`

`n_(nitrogen)= 0.321mol`

`n_(oxygen)=(7.715g)/(16g/mol)`

`n_(oxygen)= 0.482mol`

So the formula would be:

`N_(0.321)O_(0.482)`

Dividing per 0.321:

`NO_(1.5)`

In natural numbers:

`N_2O_(3)`