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Suppose you had d dollars in your bank account. You spent $22 but have at least $28 left. How much money did you have initially? Write and solve an inequality that represents this situation.

A) d + 22 ≤ 28; d ≤ 72
B) d – 22 > 28; d > 50
C) d + 22 ≥ 28; d ≥ 72
D) d – 22 ≥ 28;d ≥ 50

User Cboden
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2 Answers

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We'll if you said you spent 22 and now you have 28

28 + 22 = 50

So the answer would be
B. d – 22 > 28; d > 50
I hope this helped : )
User Blobdon
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6 votes

Answer:

D) d – 22 ≥ 28;d ≥ 50

Explanation:

Let d represents the initial money ( in dollars ) in the account,

So, after spending $ 22 the remaining amount = initial amount - $ 22 = (d-22) dollars,

According to the question,

The remaining amount ≥ $ 28

d - 22 ≥ 28

Adding 22 on both sides, ( additive property of inequality ),

d ≥ 50

Hence, the required inequality and its solution would be,

d - 22 ≥ 28; d ≥ 50

Option 'D' is correct.

User NoWhereToBeSeen
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