Question

Is △RWS ~ △QWT?

yes
no

Answer 1

Yes, it is. they are.

Answer 2

Answer: Yes ΔRWS≈ΔQWT.

Explanation:

We know that when two chords intersect each other inside a circle, the products of their segments are equal.

Therefore,
`QW* WS=TW* RW\\\Rightarrow(QW)/(RW)=(TW)/(WS)`

Now in triangle QWT and triangle RWS

∠QWT=∠RWS [Vertically opposite angles]

`(QW)/(RW)=(TW)/(WS)`

Therefore, By SAS similarity rule

ΔRWS≈ΔQWT

Therefore, yes ΔRWS≈ΔQWT.