Question

(2/3×2/3×2/3)+(1/9×1/9)×(8-2)

Answer 1

We have

`\mleft((2)/(3)*(2)/(3)*(2)/(3)\mright)+\mleft((1)/(9)*(1)/(9)\mright)*\mleft(8-2\mright)​`

First we have to solve the operations inside the parentheses

`((8)/(27))+((1)/(81))(6)`

then we solve the multiplication

`\begin{gathered} ((8)/(27))+((6)/(81)) \\ \end{gathered}`

we need to have the same denominator in order to sum fractions

`((8*81)+(6*27))/(27*81)=(648+162)/(2187)=(810)/(2187)=(10)/(27)`

the expression simplified is 10/27