Question

Write using algebra.

A bucket holds c liters of water, but a jar holds 8 liters less. How many times as much water can the bucket hold as the jar?

Answer 1

Let's just say that:
B = Bucket
J = Jar.

The amount of water J can hold is 8 liters less than B. So:
J = C - 8
(C represent the amount of water the bucket can hold)

And let's do the same for B. Since B holds C amount of water, the expression for this is:
B = C

Hope I answered your question!

Answer 2

The answer is:

The bucket may hold
`(C)/(C-8)` times the amount of water of the jar.

Explanation:

In order to determine the answer, we have to know about proportion.

When we use proportion, we want to express a fraction between two measures. It is useful to compare each other if something is more than twice or three times or whatever.

In this case, we have two measures.

C= amount of water that is holded by the bucket.

J=amount of water that is holded by the jar.

Where:

`C=J+8`

So, expressing both measure as a proportion:

`(C)/(J)=(C)/(C-8)`

Finally, the bucket may hold
`(C)/(C-8)` times the amount of water of the jar.