Question

Ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45 degrees relative to the ground. The horizontal component of the initial velocity to the nearest tenth is?

Answer 1

the vertical and horizontal components of the initial velocity can be determined by sine and cosine functions. Since it asked for the horizontal component you would use the formula "Vix= ViCosineθ" and the answer would be 8.5

Answer 2

8.5m/s

Step-by-step explanation:

Given the initial velocity to be 12m/s at an angle of 45° to the ground. The horizontal component of the velocity can be expressed as U cos (theta) where;

U is the initial velocity of the object

theta is the angle between the initial velocity and the horizontal. Mathematically, Ux = Ucos(theta)

Ux = 12cos45°

Ux = 12×1/√2

Ux = 12×√2/2

Ux = 6√2m/s

Ux = 8.48m/s

Ux = 8.5m/s(to nearest tenth)